Question

1/√7+√3-√6 rationalise​

Answer 1

$\sf \frac{1}{ \sqrt{7} + \sqrt{3} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{3} + \sqrt{6} }{ \sqrt{7} + \sqrt{3} + \sqrt{6}} = \frac{ \sqrt{7} + \sqrt{3} + \sqrt{6} }{ {( \sqrt{7} + \sqrt{3}) }^{2} - {( \sqrt{6)} }^{2} }$

$\sf = \frac{ \sqrt{7} + \sqrt{3} + \sqrt{6} }{3}$

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