Question

1/√7+√3 express with a rational denominator

Answer 1

$\huge{\underline{\tt{QUESTION:-}}}$

1/√7+√3 express with a rational denominator ?

$\huge{\underline{\tt{ANSWER:-}}}$


$\frac{1}{ \sqrt{7} + \sqrt{3} } \\ = \frac{1}{ \sqrt{7} + \sqrt{3} } \times \frac{ \sqrt{7 } - \sqrt{3} }{ \sqrt{7} - \sqrt{3} } \\ = \frac{ \sqrt{7} - \sqrt{3} }{ ({ \sqrt{7} )}^{2} - {( \sqrt{3} })^{2} } \\ = \frac{ \sqrt{7} - \sqrt{3} }{7 - 3} \\ = \frac{ \sqrt{7} - \sqrt{3} }{4}$