Question

1/√7-3 rationalize the denominator

Answer 1

Step-by-step explanation:

$\frac{1}{ \sqrt{7} - 3 } \times \frac{ \sqrt{7} + 3}{ \sqrt{7} + 3}$

$\frac{ \sqrt{7} + 3}{ {( \sqrt{7)}^{2} } - {(3)}^{2} }$

$\frac{ \sqrt{7} + 3}{7 - 9}$

$\frac{ \sqrt{7} + 3}{ - 2}$

hope it helps u

Answer 2

Answer:

$= - ( \sqrt{7} + 3) \div 2$