Math, asked by anushree53, 1 year ago

1/√7-√6 - 1/√6-√5 + 1/√5-2 - 1/√8-√7 - 1/3-√8 =?

Answers

Answered by Anonymous
1

Answer:

1/√7-√6 - 1/√6-√5 + 1/√5-2 - 1/√8-√7 - 1/3-√8 =?

Now,

1/√7-√7=√7+√6

- 1/√6-√5=√6+√5

1/√5-2=√5+2

1/√8-√7=√8+√7

1/3-√8=3+√8

=1/√7-√6 - 1/√6-√5 + 1/√5-2 - 1/√8-√7 - 1/3-√8

=√7+√6-√6-√5+√5+2-√8-√7+3+√8

=2+3=5

hence prove.



anushree53: sorry but answer is 5, but i need the procedure
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