1/√7+√6-√13 rationalize the denominator
Answers
Answered by
2
Step-by-step explanation:
7
+
6
−
13
1
=
(
7
+
6
)
2
−13
7
+
6
+
13
=
2
42
7
+
6
+
13
=
12
6
+
14
7
+
84
546
Answered by
3
Answer:
1/(√7+√6-√13)
Rationalising factor = √7+√6+√13
→ 1/(√7+√6-√13) × √7+√6+√13/(√7+√6+√13)
→ √7+√6+√13/(√7+√6-√13)(√7+√6+√13)
→ √7+√6+√13/(√7+√6)²-(√13)²
→ √7+√6+√13/(√7²+√6²+2(√7)(√6))-13
→ √7+√6+√13/13+2√42-13
→ √7+√6+√13/2√42
The denominator is still irrational. So we have to rationalise it further.
Now rationalising factor = √42
→ √7+√6+√13/2√42 × √42/√42
→ √42(√7+√6+√13)/2(√42)²
→ √42×7+√42×6+√42×13/2(42)
→ (7√6+6√7+√546)/84
→ 7√6/84 + 6√7/84 + √546/84
→ √6/12 + √7/14 + √546/84
Now the denominator is rationalised.
Step-by-step explanation:
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