Question

1/√7+√6-√13 rationalize the denominator​

Answer 1

Step-by-step explanation:

7

+

6

−

13

1

=

(

7

+

6

)

2

−13

7

+

6

+

13

=

2

42

7

+

6

+

13

=

12

6

+

14

7

+

84

546

Answer 2

Answer:

1/(√7+√6-√13)

Rationalising factor = √7+√6+√13

→ 1/(√7+√6-√13) × √7+√6+√13/(√7+√6+√13)

→ √7+√6+√13/(√7+√6-√13)(√7+√6+√13)

→ √7+√6+√13/(√7+√6)²-(√13)²

→ √7+√6+√13/(√7²+√6²+2(√7)(√6))-13

→ √7+√6+√13/13+2√42-13

→ √7+√6+√13/2√42

The denominator is still irrational. So we have to rationalise it further.

Now rationalising factor = √42

→ √7+√6+√13/2√42 × √42/√42

→ √42(√7+√6+√13)/2(√42)²

→ √42×7+√42×6+√42×13/2(42)  

→ (7√6+6√7+√546)/84  

→ 7√6/84 + 6√7/84 + √546/84  

→ √6/12 + √7/14 + √546/84

Now the denominator is rationalised.

Step-by-step explanation:

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