Question

1/√7−√6 , Rationalise the denominators of the given numbers.

Answer 1

Number = 1 / √7 - √6

Rationalizing factor = √7 + √6

Now we must multiply the rationalizing factor on both the numerator and denominator.

=> 1 * ( √7 + √6 ) / ( √7 - √6 ) * ( √7 + √6 )

=> √7 + √6 / ( √7 )² - ( √6 )²

=> √7 + √6 / 7 - 6

=> √7 + √6 / 1

=> √7 + √6

Answer 2

1/root 7 - root 6
= 1/ root7 - root 6 ×root7 + root 6 /root7 + root 6
= root 7 + root 6/ (root 7)^2-( root6)^2
=root 7 + root 6 / 7-6
= root 7 +root 6/1