Question

1/7 power 4-2x = root 7 find the value of x ​

Answer 1

Explanation:-

$\frac{1}{{7}^{4 - 2x}} = \sqrt{7} = > {7}^{ - (4 - 2x)} = {7}^{ \frac{1}{2} } = >$

${7}^{2x - 4} = {7}^{ \frac{1}{2}} = > 2x - 4 = \frac{1}{2} = >$

$4x - 8 = 1 = > 4x = 8 + 1 = 9 = >$

$4x = 9 = > x = \frac{9}{4}$

Hope it helps you.

Answer 2

The value of x ​is 9 / 4.

Given: ( 1 / 7 )^( 4 - 2x ) = √7

To Find: The value of x. ​

Solution:

• We know that if the base number is the same in an equation then the powers are also equal.

       For example: If p^q = p^r, then q = r.

Coming to the numerical, we have;

       ( 1 / 7 )^( 4 - 2x ) = √7

  ⇒  ( 7 )^(-(4 - 2x))  =  ( 7 )^1/2

Since the base ( i.e. 7 ) is the same on both sides of the equation, so we can equate the powers.

  ⇒   - ( 4 - 2x )  =  1/2

  ⇒   2x - 4 = 1/2

  ⇒   4x -  8 = 1

  ⇒   4x = 9

  ⇒    x = 9/4

Hence, the value of x ​is 9 / 4.

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