Question

(1/7) to the power 4-2x=√7.solve for x.

Answer 1

(1/7)^(4-2x)=√7
or,1/[7^(4-2x)]=7^(1/2)
or,1=[7^(4-2x)]*7^(1/2)
or,1=7^[(4-2x)+1/2]
or,1=7^[(8-4x+1)/2]
or,1=7^[(9-4x)/2]
or 7^0=7^[(9-4x)/2]
    taking power
0=(9-4x)/2
or,9-4x=0
   x=9/4

Answer 2

Answer:

x = 9/4

Step-by-step explanation:

(1/7) ^ (4-2x) = √7

(1/7) ^ (4-2x) = 7 ^ (1/2)

1/7 ^ (4-2x) = 7 ^ (1/2)

1 = 7 ^ (1/2)* 7 ^ (4-2x)

1 = 7^ ( 1/2+4-2x)

By taking LCM of power

1 = 7 ^ (9-4x/2)

1= 7 ^ (0) = 7 ^ (9-4x/2)

0 = 9-4x/2

0 = 9-4x

-9 = -4x

-9/-4 = x

minus and minus gets cancelled

9/4 = X