[1/7x-1/8] [7x2-8y2]
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Answer:
Including results for [1/7x-1/8y] [7x2-8y2]
Search only for [1/7x-1/8] [7x2-8y2]
1 7x 1 से 8 7x2 8y2
Your question is
[17⋅−1⋅18][72−82]
[\frac{1}{7} \cdot x-1 \cdot \frac{1}{8}][7x^{2}-8y^{2}][71⋅x−1⋅81][7x2−8y2]
Simplify
1
Combine multiplied terms into a single fraction
[17−1⋅18][72−82]
[17−1⋅18][72−82]
2
Multiply by 1
[17−1⋅18][72−82]
[7−1⋅18][72−82]
3
Multiply the numbers
[7−1⋅18][72−82]
[7−18][72−82]
4
Distribute
(7−18)(72−82)
(72−82)⋅7−18(72−82)
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