Math, asked by abbas0313ar, 2 months ago


[1/7x-1/8] [7x2-8y2]

Answers

Answered by santoshkumar6620
0

Answer:

Including results for [1/7x-1/8y] [7x2-8y2]

Search only for [1/7x-1/8] [7x2-8y2]

1 7x 1 से 8 7x2 8y2

Your question is

[17⋅−1⋅18][72−82]

[\frac{1}{7} \cdot x-1 \cdot \frac{1}{8}][7x^{2}-8y^{2}][71⋅x−1⋅81][7x2−8y2]

Simplify

1

Combine multiplied terms into a single fraction

[17−1⋅18][72−82]

[17−1⋅18][72−82]

2

Multiply by 1

[17−1⋅18][72−82]

[7−1⋅18][72−82]

3

Multiply the numbers

[7−1⋅18][72−82]

[7−18][72−82]

4

Distribute

(7−18)(72−82)

(72−82)⋅7−18(72−82)

Please mark as brainlist answer

Similar questions