Question

(1) 8
8. To what power (-2) should be raised to get 16? Please Answer this urgently ​

Answer 1

Answer:

2 to the power -4

Step-by-step explanation:

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Answer 2

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Let the number be = X

$⟹ \:x^{ - 2} = 16$

Make the power positive by resiprocaling the number

$⟹ ( \frac{1}{x} )^{2} = 16$

$⟹ \frac{1}{x} = \sqrt{16}$

$⟹ \frac{1}{x} = 4$

On transposing the terms :

$\star \fbox {1/4 = x}$

$\huge\sf\red{⛬ \: number = \frac{1}{4} }$

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