1 8 m
30°
. Given PQ = 1.28 cm, PR = 2.56 cm, PE = 1.8 and E, F are points on the sides PQ and PR.
PF = 3.6 cm. Is EF // QR ?
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Answer:
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10th
Maths
Triangles
Basic Proportionality Theorem
In PQR, E and F are points...
MATHS
In △PQR, E and F are points on the sides PQ and PR respectively. verify EF || QR. PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm, PF = 0.36 cm.
January 17, 2020
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Aamir Kaul
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ANSWER
The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.
It is given that PQ=1.28 cm, PR=2.56 cm, PE=0.18 cm and PF=0.36 cm.
We find the following:
EQ=PQ−PE=1.28−0.18=1.10 cm
FR=PR−PF=2.56−0.36=2.20 cm
Using the basic proportionality theorem, we have
EQ
PE
=
1.10
0.18
=0.16
FR
PF
=
2.20
0.36
=0.16
Since
EQ
PE
=
FR
PF
Hence, EF is parallel to QR.
Answer:
•: EF ll PQ
Step-by-step explanation:
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