1/8 of the length of á log is damaged. A man cuts off 3/4 of the second part. If the log is 16m
long, find the length of second log left. I want it too fast plz can any one help please!
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Answer:
let x be the length of the log
If 1/8 part is damaged, then the remaining part is
x - x/8 = 7x/8
The man cuts 3/4 of 7x/8 = (3/4)×(7x/8) = length of the second part
=21x/32
Now put x=16
=21×16/32 = 21/2 = 10.5m Ans
Therrsecond
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this is your answer
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