Question

1 - 8 x + 16 X square is equal to zero

Answer 1

16x^2 -8x +1 = 0

16x^2 - 4x -4x +1 = 0

4x( 4x -1) -( 4x-1)= 0

( 4x-1)^2 = 0

x= 1/4

Answer 2

Given $16x^{2}-8x+1$

Splitting the middle term, we get $16x^{2}-4x-4x+1$

Taking the common factor, we get $4x(4x-1)-1(4x-1)$

$=(4x-1)(4x-1)$

$=(4x-1)^{2}$

Therefore, $(4x-1)^{2}$ is $16x^{2}-8x+1$.