Question

1/8 ( - y - 3( 16 - 3y ) )

Answer 1

Answer:

1/8 = -y-3(16-3y)

1/8 =

$\ - 16y ^{2} - + 3y ^{2} - 48 + 9y ^{2}$

1/8 =

$12y ^{2} - 16y - 48$

$(12y ^{2} - 16y + 48) \\ 2se \: divaid \: karne \: par$

1/8 =

$6y ^{2} - 8y - 24$

1/8=

$3y ^{2} - 4y - 12$

1/8=

$+ - b \sqrt{b ^{2} } - 4ac \div 2a$

1/8=

$- 32 \: \: or \: + 32$

$32 \times 8$

= 256