1.80 g of glucose is dissolved in 36.00 g of water in a beaker. The total number of oxygen atoms in the solution
is ?
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Answered by
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Heya.......!!!
=> In 180 gm of glucose number of oxygen atoms are 6 NA.
=> In 1.8 gm of glucose, number of oxygen atoms = 6 NA/180 × 1.8 = 0.06 NA atoms .
=> In 18 gm of water, number of oxygen atoms are NA.
Then ,,
=> In 36.0 gm of water, number of oxygen atoms are = NA/18 × 36 = 2 NA
=>> Total number of oxygen atoms in the solution = (0.06 + 2) NA = 2.06 NA
=> 2.06 × 6.022 × 10^23
➡➡ = 12.405 × 10^23 is the Required answer .
Hope it Helps You ^_^
=> In 180 gm of glucose number of oxygen atoms are 6 NA.
=> In 1.8 gm of glucose, number of oxygen atoms = 6 NA/180 × 1.8 = 0.06 NA atoms .
=> In 18 gm of water, number of oxygen atoms are NA.
Then ,,
=> In 36.0 gm of water, number of oxygen atoms are = NA/18 × 36 = 2 NA
=>> Total number of oxygen atoms in the solution = (0.06 + 2) NA = 2.06 NA
=> 2.06 × 6.022 × 10^23
➡➡ = 12.405 × 10^23 is the Required answer .
Hope it Helps You ^_^
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Answered by
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Answer:
12.405*10^23
Explanation:
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