Question

1.80 g ofa certain metal burnt in oxygen
gave 3.0g of its oxide. 1.50 g of the samne
metal heated in steam gave 2.50 g of its

oxide. Show that these results illustrate the

law of constant proportion.

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Answer 1

Given :

• 1.80 g of a certain metal burnt in oxygen gave 3.0 gm of its oxide.
• 1.50 g of the same metal heated in steam gave 2.50 gm of its oxide.

To Find :

• Show that these results illustrate the law of constant proportion.

Required Solution :

Case ① :

• → Weight of metal = 1.80 gm
• → Weight of oxygen = (3.0 - 1.80)
• → Weight of oxygen = 1.2 gm

$\tt{:\implies \dfrac{Weight \:of \:metal}{Weight \:of \:oxygen}}$

$\tt{:\implies \cancel{\dfrac{1.80}{1.5}}}$

$\bf{:\implies \underline{ \: \: \underline{ \red{ \: \: 1.5 \: \: }} \: \: }}$

Case ② :

• → Weight of metal = 1.50 gm
• → Weight of oxygen = 2.5 - 1.50
• → Weight of oxygen = 1 gm

$\tt{:\implies \dfrac{Weight \:of \:metal}{Weight \:of \:oxygen}}$

$\tt{:\implies \cancel{\dfrac{1.50}{1}}}$

$\bf{:\implies \underline{ \: \: \underline{ \red{ \: \: 1.5 \: \: }} \: \: }}$

• In both Case ① and Case ② Proportional of metal are constant, In Case ① 1.5 and in Case ② also 1.5 that means this follow law of constant proportion.

Hence Solved !