Question

1.80g of glucose is dissolved in 36.00g of water in a beaker. The total number of oxygen atoms in the solution is ?​

Answer 1

Answer:

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Explanation:

Mass of glucose =1.80gm

Molecular mass of glucose (CC6H12O )=180gm

No. of moles = 180/1.80=10*−2 moles

Number of molecules of glucose=10*_2×6.023

=6.023×10*21

molecules of C6H12O6

Total number of oxygen atoms present in glucose =6×6.023×10*21

Number of moles of water = 36g /18g =2 moles

Number of H2O molecules =2×6.023×10*23H2Omolecules.

Therefore, no. of oxygen atoms in water =12.046×10

23

Total number of oxygen atoms present in solution (water+glucose),

12.046×10 *23+36.138×10 *21

=12.406×10*23

oxygen atoms

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