Math, asked by cnsunil1968, 9 months ago

1
81-E
cylinder and two hemispheres are cach 1-2 m. If they distribute drinking
water to 60 people in a container, each is in the shape of a cylinder of
radius 21 cm and height 50 cm, find the quantity of water left in the tanker
after distribution in litre. (-22
1-2 mif the length is 4.2 metres ​

Answers

Answered by amitnrw
3

Given :  A water container cylindrical  with two hemispherical ends . to distribute Drinking water for 6o people

To find : Water left in Tank

Solution:

Length of Tanker is 4.2 m

Radius of base of cylinder = hemisphere = 1.2/2 = 0.6 m

Length of each hemisphere = 0.6 m

Length of cylindrical part = 4.2 - 0.6 - 0.6 = 3 m

Volume of Cylinder = π r²h

= π (0.6)² * 3 m³

Volume of two hemisphere = 2 * (2/3)π r³

= (4/3) π (0.6)³

= 0.8 π (0.6)²  m³

Total Volume =  3.8 π (0.6)²  m³

= 1.368 π  m³

Volume of one container = π (21/100)² * (50/100) m³

= π (.21)² / 2   m³

Volume of 60 container = 60 *  π (.21)² / 2   m³

= 30   π (.21)²    m³

= 1.323 π   m³

Water left in Tank =  1.368 π  -  1.323 π  = 0.045 π   m³

= 0.045 π   m³

= 0.141  m³

1 m³ = 1000 litre

=> 0.141  m³  = 141 Litre

141 litre water left in Tank

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