1.82g of glucose(molar mass is 180) is dissolved in 25g of water. Calculate the molality and mole fraction of glucose.
Answers
Explanation:
(a) Molality :-
Molality = moles of solute (glucose)
mass of solvent (water)
Moles of glucose = C6H12O6
Molar mass = (12×6)+(1×2)+(16×6)
= 72+12+96
= 180
Mass of glucose = 1.82g
Therefore,,
moles = 1.82
180
= 0.01 moles
Therefore,,,it's molality =
Moles of glucose (0.01)
Mass of water(0.025)
= 0.01
0.025 molal
◾Molality = 0.4 molal
(b) Mole fraction :-
Mole of glucose = 0.01
Mole of water = 25 mass
molar mass
mass = 25g
molar mass H2O
= (1×2) +16
= 2+16
= 18
Moles = 25 = 1.388
18
Moles of glucose = 0.01
moles of water = 1.388
Mole fraction of glucose = mole of glucose
= 0.01
= 7.2×10³
Mole of water = 1.388
therefore,,
Mole fraction of glucose =
72 = 9
1000 1250
Answer:
Molality = 0.4 m
Mole fraction= 0.007
Explanation:
Given:
Mass of glucose = 1.82 g
Molar mass of glucose = 180 g/mol
Mass of water = 25 g.
1. Molality:
Molality of a solution is defined as the moles of solute per mass of solvent in kg.
Now, for the given solution, first calculate the moles of glucose.
Mass of solvent (water) = 25 g = 0.025 kg.
Therefore, the molality is determined as-
Hence, the molality of glucose solution = 0.4 m
2. Mole fraction:
Mole fraction of glucose is determined as-
Moles of glucose = 0.01 moles
Similarly, the moles of water are calculated as-
Mass of water = 25 g
Molar mass of water = 18.0 g/mol
Thus, mole fraction is-
Hence, mole fraction of glucose solution = 0.007.
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