Question

1/8a3+8/b3 pls solve​

Answer 1

Answer:

nott att allll........

Answer 2

$Given \: \frac{a^{3}}{8} + \frac{8}{b^{3}}$

$= \Big(\frac{a}{2}\Big)^{3} + \Big(\frac{2}{b}\Big)^{3}$

/* By algebraic identity */

$\boxed{ \pink{ x^{3} + y^{3} = (x+y)(x^{2}-xy+y^{2} ) }}$

$= \Big( \frac{a}{2} + \frac{2}{b}\Big) [\Big( \frac{a}{2}\Big)^{2} - \frac{a}{2} \times \frac{2}{b} + \Big( \frac{2}{b}\Big)^{2}]$

$= \Big( \frac{a}{2} + \frac{2}{b}\Big) [ \frac{a^{2}}{4} - \frac{a}{b} + \frac{4}{b^{2}}]$

Therefore.,

$\red{ Factors \: of \: \frac{a^{3}}{8} + \frac{8}{b^{3}}}$

$\green { = \Big( \frac{a}{2} + \frac{2}{b}\Big) \Big( \frac{a^{2}}{4} - \frac{a}{b} + \frac{4}{b^{2}}\Big)}$

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