1/8p^3+1/4p^2q+1/6pq^2+1/27q^3
sumeet5581:
Plz answer the question fast
Can anybody help
Question is not clear. Instead, please click a photo of your question
Answers
Answered by
0
1/8p^3+ 1/4p^2q+1/6pq^2+1/27q^3
=(1/2p)^3 + 3*(1/2p)^2*1/3q + 3*1/2p*
(1/3q)^2 + (1/3q)^3 =(1/2p+1/3p)^3 =
(1/2p+1/3q) (1/2p+1/3q) (1/2p+1/3q)
=(1/2p)^3 + 3*(1/2p)^2*1/3q + 3*1/2p*
(1/3q)^2 + (1/3q)^3 =(1/2p+1/3p)^3 =
(1/2p+1/3q) (1/2p+1/3q) (1/2p+1/3q)
Similar questions