1+8x^3 [factorize]
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Given
1 + 8x³
Factorise it
Solution
Applying identity to solve this Factorise
a³ + b³ = (a + b)(a² - ab + b²)
= 1 + 8x³
= (1)³ + (2x)³
= (1 + 2x) [(1)² - 1×2x + (2x)²]
= (1 + 2x) [1 - 2x + 4x²]
Some important identities
- (a+b)² = a² + b² +2ab
- (a-b)² = a² + b² - 2ab
- (a+b)³ = a³ + b³ + 3ab(a+b)
- (a-b)³ = a³ -b³ - 3ab(a-b)
- a² - b² = (a+b)(a-b)
- a³ + b³ = (a+b)(a² - ab +b²)
- a³ - b³ = (a-b)(a² + ab +b²)
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