Question

1/9(18/5+-3/20)=1/9×18/5+1/9×(-3/20)

Answer 1

Answer:

$\frac{1}{9}\left(\frac{18}{5}+\frac{\left(-3\right)}{20}\right)=\frac{1}{9}\cdot \frac{18}{5}+\frac{1}{9}\left(-\frac{3}{20}\right)\quad :\quad \mathrm{True}$

Step-by-step explanation:

$\frac{1}{9}\left(\frac{18}{5}+\frac{\left(-3\right)}{20}\right)=\frac{1}{9}\cdot \frac{18}{5}+\frac{1}{9}\left(-\frac{3}{20}\right)$

$\mathrm{RHS}$$\frac{1}{9}\left(\frac{18}{5}+\frac{-3}{20}\right)$

$=\frac{1}{9}\left(\frac{18}{5}-\frac{3}{20}\right)$

$=\frac{1}{9}\cdot \frac{69}{20}$

$=\frac{1\cdot \:23}{3\cdot \:20}$

$=\frac{23}{3\cdot \:20}$

$=\frac{23}{60}$

$\mathrm{LHS}$  $\frac{1}{9}\cdot \frac{18}{5}+\frac{1}{9}\left(-\frac{3}{20}\right)$

$=\frac{1}{9}\cdot \frac{18}{5}-\frac{1}{9}\cdot \frac{3}{20}$

$=\frac{2}{5}-\frac{1}{60}$

$=\frac{24}{60}-\frac{1}{60}$

$=\frac{24-1}{60}$

$=\frac{23}{60}$

$\frac{23}{60}=\frac{23}{60}$

$Both\:sides\:are\:equal$