Question

1/9+√5+√6 rationalise the denominator

Answer 1

Answer:

1/9+√5+√6= 1/9+(√5+√6)× 9-(√5+√6)/9-(√5+√6)

= 9-(√5+√6)/ (9)²- (√5+√6)²

= 9-(√5+√6)/81-(5+6+2√30)

= 9-(√5+√6)/81-(11+2√30)

= 9-(√5+√6)/81-11-2√30

. = 9- (√5+√6)/70-2√30

= 9-(√5+√6)/(70-2√30) × (70+2√30)/(70+2√30)

= 70(9-√5-√6)+2√30(9-√5-√6)/(70)²-(2√30)²

=(630-70√5-70√6+18√30-2√150-2√180)/4900-120

=(630-70√5-70√6+ 18√30-10√6-12√5)/4780

=( 630-84√5-80√6+18√30)/4780

=2(315-42√5-40√6+9√30-5√6-6√5)/ 4780

= (315-42√5-40√6+9√30-5√6-6√5)/2390