Question

-1 9. A particle of mass 2 kg is moving on a circular path of radius 10 m with a speed of 5 ms' and its speed is increasing at a rate of 3 ms. Find the force acting on the particle. (a) 5 N (b) 10 N (c) 12 N (d) 14 N -1
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Answer 1

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Answer 2

Given,

Mass of the object (m)=2 kg

The radius of the circular path(r)=10 m

Speed of object(v)=5m/s

Rate of change of speed=3m/s

To find,

Force acting on the particle (F)

Solution,

Using the formula,

Force acting on an object moving on a circular path (F) = $\frac{mv^{2} }{r}$

Substituting the values given, we get

⇒F=$\frac{(2)(5^{2} )}{10}$

⇒F=5N

Hence, the force acting on the object is 5N. Hence, the correct answer is option a