Question

1)
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9.
If (x + a) is the factor of the polynomials (x2+px +q)
and (x2 + mx + n), then the value of 'a' is
(a) n-q/m-q (b) m-p/n-q (c) q-n/m-p (d) m-p/q-n
.​

Answer 1

Step-by-step explanation:

$let \: p(x) = {x}^{2} + px + q \\ and \: \: f(x) = {x}^{2} + mx + n \\ \\ g(x) = x + a \\ \\ \\ \\ crossponding \: eq. \: of \: g(x) = x + a = 0 \\ x = - a \\ \\ putting \: the \: value \: in \: p(x) \\ \\ \\ \\ {( - a)}^{2} + p( - a) + q = 0 \\ \\ { {a}^{2} - pa + q}^{2} = 0 \\ \\ and \: putting \: the \: value \: of \: x \: in \: f(x) \\ \\ ( { - a)}^{2} + m( - a) + n = 0 \\ \\ {a}^{2} - ma + n = 0 \\ \\ so \\ \\ {a }^{2} - pa + q = {a}^{2} - ma + n \\ \\ - pa + q = - ma + n$

Answer 2

Answer:

Hope this helps you ✌️✌️