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9. The number of digits in 2^512 x 3^10 is log 2 =0.3010: log 3 = 0.4771
(a) 158
(b) 159
(b) 157
(d) 160
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Answer:
og5512 = log512/log5 = log29log(10/2) =9log2log10−log2 =9*0.30101−0.3010 =2.709/0.699 =2709/699 =3.876
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