Question

1
9. The value of K for which kx(x-
2)+6=0 has equal roots is *
O a) 4
O b) 5
Oc) 3
O d) 6​

Answer 1

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Answer 2

Answer:

Answer is 6.

Step-by-step explanation:

kx(x-2)+6=0

kx^2-2kx+6=0

by discriminant rule:b^2-4ac

(-2k)^2-(4)(k)(6)=0

4k^2-24k=0

4k=24

k=6