Question

1.98 whole cube + 0.02 whole cube + 1.98×0.12

Answer 1

The answer is 8

Step-by-step explanation:

Given:

$= > \: {1.98}^{3} + {0.02}^{3} + 1.98 \times 0.12$

As we know that,

$= > \: {(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab \times (a + b)$

Similarly, the given equation is also written as

$= > \: {1.98}^{3} + {0.02}^{3} + 3 \times 1.98 \times 0.02 \times (1.98 + 0.02)$

So,

$= > \: {(1.98 + 0.02)}^{3}$

$= > \: {2}^{3}$

$= > \: 8$

So, the answer is 8.