Question

1/9x^2-2/3x+1 factorise ​

Answer 1

Answer:

$\frac{x^{2}}{9}-\frac{2x}{3}+1= \left(\frac{x}{3}-1\right)\left(\frac{x}{3}-1\right)$

Step-by-step explanation:

$\frac{x^{2}}{9}-\frac{2x}{3}+1$

$=\left(\frac{x}{3}\right)^{2}-2\times \frac{x}{3}\times 1 + 1^{2}$

$= \left(\frac{x}{3}-1\right)^{2}$

/* By algebraic identity:

a²-2ab+b² = (a-b)² */

$= \left(\frac{x}{3}-1\right)\left(\frac{x}{3}-1\right)$

Therefore,

$\frac{x^{2}}{9}-\frac{2x}{3}+1= \left(\frac{x}{3}-1\right)\left(\frac{x}{3}-1\right)$

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Answer 2

Answer:

Step-by-step explanation: