Question

[1/9x^3+3]^2 expand it​

Answer 1

$\large{\implies{Answer}}$

$= ( \frac{1}{9} x {}^{3} + 3) {}^{2} \\ = (\frac{1}{9} {x}^{3}) {}^{2} +( 3) {}^{2} + 2( \frac{1}{9 } x {}^{3} )(3) \\ = \frac{x {}^{6} }{81} + 9 + \frac{2x {}^{3} }{3}$

Answer 2

here is your answer ❤️..