Question

1/9x2-2/3x+1=0 using quadratic equations

Answer 1

$\frac{1}{9} {x}^{2} - \frac{2}{3} x + 1 = 0 \\ ( \frac{1}{3} {x)}^{2} - 2.( \frac{1}{3} x).1 + {(1)}^{2} \\ {( \frac{1}{3}x - 1) }^{2} \\ ( \frac{1}{3} x - 1)( \frac{1}{3} x - 1) \\ hope \: this \: is \: helpful$

Answer 2

Answer:

3,3 two equal roots

Step-by-step explanation:

1/9x²-2/3x+2=0. (dividing both sides by 1/9)

x²-6x+9=0

x²-3x-3x+9=0

x(x-3)-3(x-3)=0

(x-3) (x-3)=0

therefore x=3, x=3