Question

1. A 0.24 g sample of compound of oxygen and boron was found
by analysis to contain 0.096 g of boron and 0.144 g of een
Calculate the percentage composition of the compound by
weight.​

Answer 1

$\bigstar$ Answer $\bigstar$

$\checkmark$ Given:

A 0.24 g sample of compound of oxygen and boron was found  by analysis to contain 0.096 g of boron and 0.144 g of Oxygen

$\checkmark$ To Find:

Calculate the percentage composition of the compound by  weight

$\checkmark$ Solution:

Given that,

Mass of Compound = 0.24 g

Mass of Boron = 0.096 g

Mass of Oxygen = 0.144 g

According to the Question,

We are asked to Calculate the percentage composition of the compound by  weight

Hence,

Percentage (%) Composition by weight

$\sf \implies \left(\dfrac{Mass \ of \ Element }{Mass \ of \ Compound}\right) \times 100$

Hence,

Percentage (%) Composition by weight of Boron

$\sf \implies \left(\dfrac{Mass \ of \ Boron}{Mass \ of \ Compound}\right) \times 100$

Given that,

Mass of Compound = 0.24 g

Mass of Boron = 0.096 g

Hence,

Substituting the values,

We get,

$\sf \implies Boron= \dfrac{0.096}{0.24} \times 100$

$\red{\sf \implies Boron=40 \%}$

We are also asked to find the Percentage (%) Composition by weight of Oxygen

Hence,

Percentage (%) Composition by weight of Oxygen

$\sf \implies \left(\dfrac{Mass \ of \ Oxygen}{Mass \ of \ Compound}\right) \times 100$

Given that,

Mass of Compound = 0.24 g

Mass of Oxygen = 0.144 g

Hence,

Substituting the values,

We get,

$\sf \implies Oxygen= \dfrac{0.144}{0.24} \times 100$

$\pink{\sf \implies Oxygen=60 \%}$

Also, the % Composition of Elements add up to 100 %

⇒ % Boron + % Oxygen

⇒ 40 % + 60 % = 100 %

Answer 2

★ Answer \bigstar★

\checkmark✓ Given:

A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of Oxygen

\checkmark✓ To Find:

Calculate the percentage composition of the compound by weight

\checkmark✓ Solution:

Given that,

Mass of Compound = 0.24 g

Mass of Boron = 0.096 g

Mass of Oxygen = 0.144 g

According to the Question,

We are asked to Calculate the percentage composition of the compound by weight

Hence,

Percentage (%) Composition by weight

\sf \implies \left(\dfrac{Mass \ of \ Element }{Mass \ of \ Compound}\right) \times 100⟹(

Mass of Compound

Mass of Element

We are also asked to find the Percentage (%) Composition by weight of Oxygen

Hence,

Percentage (%) Composition by weight of Oxygen

\sf \implies \left(\dfrac{Mass \ of \ Oxygen}{Mass \ of \ Compound}\right) \times 100⟹(

Mass of Compound

Mass of Oxygen

)×100

Given that,

Mass of Compound = 0.24 g

Mass of Oxygen = 0.144 g

Hence,

Substituting the values,

We get,

\sf \implies Oxygen= \dfrac{0.144}{0.24} \times 100⟹Oxygen=

0.24

0.144

×100

\pink{\sf \implies Oxygen=60 \%}⟹Oxygen=60%

Also, the % Composition of Elements add up to 100 %

⇒ % Boron + % Oxygen

⇒ 40 % + 60 % = 100 %