Math, asked by Shivamd5497, 9 months ago

1/a+1/b+1/c=1 abc=2 then ab^2c^2+a^2bc^2+a^2b^2c

Answers

Answered by 888subhash
1

1/a + 1/b +1/c = 1

LCM = bc + ac + ab / abc = 1

bc + ac + ab = abc

ab + bc + ac = 2

ab^2 c^2 + a^ bc^2 + a^2 b^2 C

abc ( bc + ac + ab )

2. (2)

= 4

Hope it helps .

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