Question

1/a,1/b and 1/c are in A.P show that : bc,ca and ab are also in A.P <br /><br />hint :<br />multiply each given term by abc. ​

Answer 1

Answer:

Step-by-step explanation:

BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST

Answer 2

Step-by-step explanation:

Given: (1/a), (1/b) and (1/c) are in A.P.

⇒ (1/b) - (1/a) = (1/c) - (1/b)

Multiply both sides by abc, we get

⇒ ac - bc = ab - ac

⇒ ac + ac = ab + bc

⇒ 2ac = ab + bc

∴ bc,ca and ab are in A.P

Hope it helps!