1/a, 1/b and 1 /C are in AP. Show that : bc, ca and ab are also in AP.
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If three numbers are in AP then a,b,c
then 2b=a+c
here,
2/b = 1/a+1/c
2/b = (a+c)/ac
2ac = ab+bc
hence, ab,ac,bc are in AP where ac is the middle term
please mark it as the brainliest answer
then 2b=a+c
here,
2/b = 1/a+1/c
2/b = (a+c)/ac
2ac = ab+bc
hence, ab,ac,bc are in AP where ac is the middle term
please mark it as the brainliest answer
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