Question

1/a,1/b and 1/c are in AP then prove that bc ,ca and ab are in AP​

Answer 1

Answer:

1/a ,1/b,1/c are in AP

Theorem : when we multiply terms in an AP by a constant k, the resulting terms also will be in an AP.

So now multiply 1/a,1/b,1/c by abc we will get bc, ac and ab which are in AP.

Hope it helps you.