Question

(1) a= 10,
d=10 find first four AP​

Answer 1

Answer:

since a=10 d=10

we know that

1st term of AP is a=10

2nd term of AP is a+d=20

3rd term of AP is a+2d=30

4th term of AP is a+3d=40

Step-by-step explanation:

there the series of AP is

10,20,30,40...

4th term of AP=40

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Answer 2

$\huge\mathtt\purple{Question}$

A = 10

D = 10

To find the first four AP.

$\huge\mathtt\purple{Formula\:used}$

$\longrightarrow$ AP = a + (n - 1)d

$\huge\mathtt\purple{Short\:cut\:fact}$

For 1st four terms:-

$\longrightarrow$ $a_1$ = a

$\longrightarrow$ $a_2$ = a + d

$\longrightarrow$ $a_3$ = a + 2d

$\longrightarrow$ $a_4$ = a + 3d

$\huge\mathtt\purple{Given}$

a = 10 and d = 10

$\huge\mathtt\purple{Solution}$

Using the above formula,

$\longrightarrow$ $a_1$ = 10

$\longrightarrow$ $a_2$ = 10 + 10 = 20

$\longrightarrow$ $a_3$ = 10 + 2(10) = 30

$\longrightarrow$ $a_4$ = 10 + 3(10) = 40

Hence, from the above context we get that the following first four AP is 10, 20, 30, 40.