Question

1) a+10 when a = 6
2) b-3 when b = 120
3) 2i + 2v when i = 3 and v = 2
4) 24/k - 3 when k = 8

Answer 1

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If x=3k+2 and y=2k−1 is a solution equation 4x−3y+1=0, find the value of k

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Solution

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It is given that 4x−3y+1=0

Now by substituting the value of x and y in the equation

4(3k+2)−3(2k−1)+1=0

On further calculation

12k+8−6k+3+1=0

6k+12=0

So we get

6k=−12

By division

k=−2

★Hope it's Helps You....

Answer 2

Answer:

1) 6 +10=16

2) 120-3 =118

3) 2×3+2×2 =10

4) 24÷8-3 = 0