Question

1/a^2+1/b^2=1/ab than a^3+b^3=?​

Answer 1

Answer:

(a+b) = a²+b²+2ab

Step-by-step explanation:

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Answer 2

Answer:

a³ + b³ = 0

Step-by-step explanation:

$\frac{1}{ {a}^{2} } + \frac{1}{ {b}^{2} } = \frac{1}{ab}$

Simplifying —

$\frac{ {a}^{2} + {b}^{2} }{ ({ab)}^{2} } = \frac{1}{ab}$

Cancelling out —

${a}^{2} + {b}^{2} = ab$

Now, in the question —

${a}^{3} + {b}^{3}$

$= (a + b)( {a}^{2} - ab + {b}^{2} )$

$= (a + b)( {a}^{2} + {b}^{2} - ab)$

We know that a²+b² = ab (see above)

$= (a + b)(ab - ab)$

$= (a + b) \times 0$

$= 0 \: \: \: \: \: (ans)$

So the answer is 0

Hope this helps you :)