Question

1. A 20 Kg load is suspended by a wire of cross
section 0.4 mm². The stress produced in N/m² is
1) 4.9 x 10-6
2) 4.9 x 108
3) 49 × 108
4) 2.45 x 106​

Answer 1

Answer:

4.9 x 10^ 8 or option (3)

Explanation:

we know ;

stress = force applied

-------------------

unit area

so, => 20 x 9.81

----------------

0.4 x 10^-6

Hence, => 4.9 x 10^8 N/m^2

Answer 2

Stress is 0.0000784

Explanation:

We know that, Stress is defined as product of Force and Area.

Or Stress = FORCE x AREA

Stress = 20 x 9.8 x 0.4 x $10^-^6$

Stress = 0.0000784

Hence, The Stress calculated is 0.0000784