Question

1. A 2500 kg truck moving at 10.00 m/s strikes a car waiting at a traffic light,
hooking bumpers. The two continue to move together at 7.00 m/s. What was the
mass of the struck car?​

Answer 1

Answer:

hey friend

Explanation:

Initial momentum = 2500(10) = 25000 kg m/s

Final momentum = (2500 + m)7

25000 = 17500 + 7m

7m = 7500

m = 1071.43 kg..

HOPE IT HELPS YOU

BRAINLIEST PLSS

Answer 2

Given:

Mass of the truck, $m_1=2500kg$

The initial velocity of the truck, $u_1=10.0m/s$

The final velocity of the truck, $v_1=7m/s$

The initial velocity of the struck car, $u_2=0$

The final velocity of the struck car, $v_2=7m/s$

To Find:

Mass of the struck car, $m_2=?$

Solution:

From the law of conservation of linear momentum, we know that the total linear momentum after a collision of a system is equal to the total linear momentum before the collision.

So, solving the following equation for $m_2$,

   $m_1u_1+m_2u_2=m_1v_1+m_2v_2$

⇒ $2500(10)+m_2(0)=2500(7)+m_2(7)$

⇒ $7m_2+17500=25000$

⇒ $m_2=1071.4kg$

Hence, the mass of the struck car is equal to 1071.4 kg.