1. a - [2b - {3a - (2b - 3c)}]
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Step-by-step explanation:
We first remove the innermost grouping symbol ( ), then { } and then [ ]
We have,
a–[2b–{3a–(2b−3c)}]
=a–[2b–{3a–2b+3c}]
=a–[2b–3a+2b–3c]
=a–2b+3a–2b+3c
Rearranging and collecting the like terms, we get:
=a–3a–2b–2b+3c
=4a–4b+3c
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Answer:
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