Math, asked by tahirali76442, 9 months ago

(1). a, 2b, 3c, 6abc .
(2). a, 2b, 3c.

Answers

Answered by ItzStrawBerry

13

a,2b,3c,6abc

a,2b,3c,6abc=(a)×(2b)×(3c)×(6abc)

a,2b,3c,6abc=(a)×(2b)×(3c)×(6abc)=36a 2b 2 c 2

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