Question

1/a=2m and b2m+1, show that 8_α23=2m+1​

Answer 1

Answer:

Let a=m

2

−1

b=2m

c=m

2

+1

using pythagoras theorem, a

2

+b

2

=c

2

So, (m

2

−1)

2

+4m

2

=(m

2

+1)

2

m

4

+1−2m

2

+4m

2

=(m

2

+1)

2

m

4

+2m

2

+1=(m

2

+1)

2

(m

2

+1)

2

=(m

2

+1)

2

Since LHS=RHS , we can say that a,b,c always form pythagorean triplet.