Question

1/a^3+1/b^3+1/c^3=0 prove that (a+b+c)^3=27abc​

Answer 1

$answer$

If a^1/3 + b^1/3 + c^1/3 = 0 , then the value of ( a + b + c )^3 will be:

Answer 2

Answer:

1/a^3+1/b^3+1/c^3=0 prove that (a+b+c)^3=27abc

yes this prove that

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