1. A 4.0 kg object moves a dictance of 7.9 m under the action of a constant force of 5.6 n.how much work is done on the object? 2.Kyle pushes a 50 kg sackof rice across a level of floor by a horizontal force 35.0 n againt a frictional force of 12.0 n.he succeded in moving the sack to a distance of 35.0 m.how much work is done by (a) kyle,(b) friction,and (c) force of gravity? 3. A shopper does a 110.0 j of work in pushing a shopping cart by a force of 33.0 n to a distance of 8.25 m. at what angle is the force applied with respect to the ground?
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Answer:
Work = Distance x Force
Work = 7.9m x 5.6N
Work = 44.24J
The J represents Joules.
The mass of the object is irrelevant here, as 5.6N of force on a 4kg object is the same as 5.6N of force on a 10kg object
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Answer:
Work = Distance x Force
Work = 7.9m x 5.6N
Work = 44.24J
The J represents Joules.
The mass of the object is irrelevant here, as 5.6N of force on a 4kg object is the same as 5.6N of force on a 10kg object
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