Question

1
(a) 6,71,428 and 7,41,082
(b) 84,082 and 7,42,351
(c) 48,617 and 8,23,417
12
there
5 Find the sum of the place values of 4 in the following pairs of numbers.​

Answer 1

Answer:

a) place value of 4 in 671428 = 400

place value of 4 in 741082 = 40000

Therefore, required sum = 400 + 40000

= 40400

b) place value of 4 in 84082= 4000

place value of 4 in 742351= 40000

Therefore, required sum = 4000 + 40000

= 44000

c) place value of 4 in 48617 = 40000

place value of 4 in 823417 = 400

Therefore, required sum = 40000 + 400

= 40400