1+a
6. If a = cos 0 + i sino, find the value of
1-a
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1+a
6. If a = cos 0 + i sino, find the value of
1-a
1+a
6. If a = cos 0 + i sino, find the value of
1-a
A=cosθ+isinθ
⇒
1−A
1+A
=
1−cosθ−isinθ
1+cosθ+isinθ
=
(1−cosθ−isinθ)
(1+cosθ+isinθ)
1−cosθ+isinθ)
(1−cosθ+isinθ)
=
(1−cosθ)
2
−(isinθ)
2
1+cosθ+isinθ−cos
2
θ−cosθ−isinθcosθ+isinθ+isinθcosθ+i
2
sin
2
θ
=
(1−2cosθ+cos
2
θ)−i
2
sin
2
θ
1+2isinθ−cos
2
θ−sin
2
θ
=
2−2cosθ
1+2isinθ−1
=
1−cosθ
isinθ
⇒
1−(1−2sin
2
2
θ
)
i×2sin
2
θ
cos
2
θ
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