Question

1.
A
A ABC and A DBC are two isosceles triangles on
the same base BC and vertices A and D are on the
same side of BC (see Fig. 7.39). If AD is extended
to intersect BC at P, show that
D
(1) A ABD=AACD
(ii) A ABP=AACP
(1) AP bisects Z A as well as Z D.
B
P
(iv) AP is the perpendicular bisector of BC.
Fig. 7.39​

Answer 1

Answer:

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